Electrostatics Question 613
Question: Two capacitors of capacitances $ 3\mu F $ and $ 6\mu F $ are charged to a potential of 12 V each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be [KCET 2002]
Options:
A) 6 volt
B) 4 volt
C) 3 volt
D) Zero
Show Answer
Answer:
Correct Answer: B
Solution:
$ V=\frac{C _{1}V _{1}-C _{2}V _{2}}{C _{1}+C _{2}}=\frac{6\times 12-3\times 12}{3+6}=4volt $
