Electrostatics Question 589

Question: In the given network capacitance, $ C _{1}=10\mu F,C _{2}=5\mu F $ and $ C _{3}=4\mu F $ . What is the resultant capacitance between A and B [Pb. PMT 1999]

Options:

A) 2.2$ \mu F $

B) 3.2$ \mu F $

C) 1.2$ \mu F $

D) 4.7$ \mu F $

Show Answer

Answer:

Correct Answer: B

Solution:

$ C=\frac{(C _{1}+C _{2})\times C _{3}}{(C _{1}+C _{2})+C _{3}} $

$ =\frac{(5+10)\times 4}{5+10+4}=\frac{60}{19}=3.2\mu F $



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