Electrostatics Question 589

Question: In the given network capacitance, C1=10μF,C2=5μF and C3=4μF . What is the resultant capacitance between A and B [Pb. PMT 1999]

Options:

A) 2.2μF

B) 3.2μF

C) 1.2μF

D) 4.7μF

Show Answer

Answer:

Correct Answer: B

Solution:

C=(C1+C2)×C3(C1+C2)+C3

=(5+10)×45+10+4=6019=3.2μF



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