Electrostatics Question 589
Question: In the given network capacitance, $ C _{1}=10\mu F,C _{2}=5\mu F $ and $ C _{3}=4\mu F $ . What is the resultant capacitance between A and B [Pb. PMT 1999]
Options:
A) 2.2$ \mu F $
B) 3.2$ \mu F $
C) 1.2$ \mu F $
D) 4.7$ \mu F $
Show Answer
Answer:
Correct Answer: B
Solution:
$ C=\frac{(C _{1}+C _{2})\times C _{3}}{(C _{1}+C _{2})+C _{3}} $
$ =\frac{(5+10)\times 4}{5+10+4}=\frac{60}{19}=3.2\mu F $
