Electrostatics Question 588

Question: A capacitor of 20μF is charged to 500 volts and connected in parallel with another capacitor of 10μF and charged to 200 volts . The common potential is [BHU 1997; CBSE PMT 2000; MH CET 1999; BHU 2004]

Options:

A) 200 volts

B) 300 volts

C) 400 volts

D) 500 volts

Show Answer

Answer:

Correct Answer: C

Solution:

V=V1C1+V2C2C1+C2

=500×20+200×1020+10=400V



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