Electrostatics Question 588

Question: A capacitor of $ 20\mu F $ is charged to $ 500\ volts $ and connected in parallel with another capacitor of $ 10\mu F $ and charged to $ 200\ volts $ . The common potential is [BHU 1997; CBSE PMT 2000; MH CET 1999; BHU 2004]

Options:

A) $ 200\ volts $

B) $ 300\ volts $

C) $ \text{400 }volts $

D) $ \text{500 }volts $

Show Answer

Answer:

Correct Answer: C

Solution:

$ V=\frac{V _{1}C _{1}+V _{2}C _{2}}{C _{1}+C _{2}} $

$ =\frac{500\times 20+200\times 10}{20+10}=400V $



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