Electrostatics Question 588
Question: A capacitor of $ 20\mu F $ is charged to $ 500\ volts $ and connected in parallel with another capacitor of $ 10\mu F $ and charged to $ 200\ volts $ . The common potential is [BHU 1997; CBSE PMT 2000; MH CET 1999; BHU 2004]
Options:
A) $ 200\ volts $
B) $ 300\ volts $
C) $ \text{400 }volts $
D) $ \text{500 }volts $
Show Answer
Answer:
Correct Answer: C
Solution:
$ V=\frac{V _{1}C _{1}+V _{2}C _{2}}{C _{1}+C _{2}} $
$ =\frac{500\times 20+200\times 10}{20+10}=400V $
