Electrostatics Question 524
Question: Four plates of equal area $ A $ are separated by equal distances $ d $ and are arranged . The equivalent capacity is
Options:
A) $ \frac{2{\varepsilon _{0}}A}{d} $
B) $ \frac{3{\varepsilon _{0}}A}{d} $
C) $ \frac{3{\varepsilon _{0}}A}{d} $
D) $ \frac{{\varepsilon _{0}}A}{d} $
Show Answer
Answer:
Correct Answer: A
Solution:
The given circuit is equivalent to a parallel combination two identical capacitors
Hence equivalent capacitance between A and B is C = $ \frac{{\varepsilon _{0}}A}{d}+\frac{{\varepsilon _{0}}A}{d} $
$ =\frac{2{\varepsilon _{0}}A}{d} $
