Electrostatics Question 524

Question: Four plates of equal area $ A $ are separated by equal distances $ d $ and are arranged . The equivalent capacity is

Options:

A) $ \frac{2{\varepsilon _{0}}A}{d} $

B) $ \frac{3{\varepsilon _{0}}A}{d} $

C) $ \frac{3{\varepsilon _{0}}A}{d} $

D) $ \frac{{\varepsilon _{0}}A}{d} $

Show Answer

Answer:

Correct Answer: A

Solution:

The given circuit is equivalent to a parallel combination two identical capacitors

Hence equivalent capacitance between A and B is C = $ \frac{{\varepsilon _{0}}A}{d}+\frac{{\varepsilon _{0}}A}{d} $

$ =\frac{2{\varepsilon _{0}}A}{d} $



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