Electrostatics Question 500
Question: An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be [MHCET 2004]
Options:
A) $ 1.7\times {{10}^{-11}}N/C $
B) $ 5.0\times {{10}^{-11}}N/C $
C) $ 5.5\times {{10}^{-11}}N/C $
D) 56 N/C
Show Answer
Answer:
Correct Answer: C
Solution:
$ E=\frac{F}{q}=\frac{mg}{e} $
$ =\frac{9\times {{10}^{-31}}\times 9.8}{1.6\times {{10}^{-19}}}=5.5\times {{10}^{-11}}N/C $
