Electrostatics Question 500

Question: An electron experiences a force equal to its weight when placed in an electric field. The intensity of the field will be [MHCET 2004]

Options:

A) $ 1.7\times {{10}^{-11}}N/C $

B) $ 5.0\times {{10}^{-11}}N/C $

C) $ 5.5\times {{10}^{-11}}N/C $

D) 56 N/C

Show Answer

Answer:

Correct Answer: C

Solution:

$ E=\frac{F}{q}=\frac{mg}{e} $

$ =\frac{9\times {{10}^{-31}}\times 9.8}{1.6\times {{10}^{-19}}}=5.5\times {{10}^{-11}}N/C $



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