Electrostatics Question 493

Question: A bullet of mass 2 gm is having a charge of $ 2\mu C $ . Through what potential difference must it be accelerated, starting from rest, to acquire a speed of $ 10m/s $ [CBSE PMT 2004]

Options:

A) 5 kV

B) 50 kV

C) 5 V

D) 50 V

Show Answer

Answer:

Correct Answer: B

Solution:

By using $ \frac{1}{2}mv^{2}=QV $

therefore $ \frac{1}{2}\times 2\times {{10}^{-6}}\times {{(10)}^{2}}=2\times {{10}^{-6}}V $

therefore $ V=50kV $



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