Electrostatics Question 493
Question: A bullet of mass 2 gm is having a charge of $ 2\mu C $ . Through what potential difference must it be accelerated, starting from rest, to acquire a speed of $ 10m/s $ [CBSE PMT 2004]
Options:
A) 5 kV
B) 50 kV
C) 5 V
D) 50 V
Show Answer
Answer:
Correct Answer: B
Solution:
By using $ \frac{1}{2}mv^{2}=QV $
therefore $ \frac{1}{2}\times 2\times {{10}^{-6}}\times {{(10)}^{2}}=2\times {{10}^{-6}}V $
therefore $ V=50kV $
