Electrostatics Question 476
Question: There are two equipotential surface . The distance between them is r. The charge of -q coulomb is taken from the surface A to B, the resultant work done will be [MP PMT 1986; CPMT 1986, 88]
Options:
A) $ W=\frac{1}{4\pi {\varepsilon _{o}}}\frac{q}{r} $
B) $ W=\frac{1}{4\pi {\varepsilon _{0}}}\frac{q}{r^{2}} $
C) $ W=-\frac{1}{4\pi {\varepsilon _{0}}}\frac{q}{r^{2}} $
D) W = zero
Show Answer
Answer:
Correct Answer: D
Solution:
The work done is given by $ =q(V _{2}-V _{1})=0 $
