Electrostatics Question 476

Question: There are two equipotential surface . The distance between them is r. The charge of -q coulomb is taken from the surface A to B, the resultant work done will be [MP PMT 1986; CPMT 1986, 88]

Options:

A) $ W=\frac{1}{4\pi {\varepsilon _{o}}}\frac{q}{r} $

B) $ W=\frac{1}{4\pi {\varepsilon _{0}}}\frac{q}{r^{2}} $

C) $ W=-\frac{1}{4\pi {\varepsilon _{0}}}\frac{q}{r^{2}} $

D) W = zero

Show Answer

Answer:

Correct Answer: D

Solution:

The work done is given by $ =q(V _{2}-V _{1})=0 $



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