SATHEE: Electrostatics Question 450

Electrostatics Question 450

Question: If 3 charges are placed at the vertices of equilateral triangle of charge -q? each. What is the net potential energy, if the side of equilateral $Δ$ is l cm [AIEEE 2002]

Options:

A) $\frac{1}{4 π ε_{0}} \frac{q^{2}}{l}$

B) $\frac{1}{4 π ε_{0}} \frac{2 q^{2}}{l}$

C) $\frac{1}{4 π ε_{0}} \frac{3 q^{2}}{l}$

D) $\frac{1}{4 π ε_{0}} \frac{4 q^{2}}{l}$

Show Answer

Answer:

Correct Answer: C

Solution:

$U = \frac{1}{4 π ε_{0}} . \frac{Q_{1} Q_{2}}{r};$

net potential energy $U_{n e t} = 3 \times \frac{1}{4 π ε_{0}} . \frac{q^{2}}{l}$

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Electrostatics Question 450

Question: If 3 charges are placed at the vertices of equilateral triangle of charge -q? each. What is the net potential energy, if the side of equilateral Δ is l cm [AIEEE 2002]

Options:

Answer:

Solution:

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Question: If 3 charges are placed at the vertices of equilateral triangle of charge -q? each. What is the net potential energy, if the side of equilateral $Δ$ is l cm [AIEEE 2002]