Electrostatics Question 450

Question: If 3 charges are placed at the vertices of equilateral triangle of charge -q? each. What is the net potential energy, if the side of equilateral $ \Delta $ is l cm [AIEEE 2002]

Options:

A) $ \frac{1}{4\pi {\varepsilon _{0}}}\frac{q^{2}}{l} $

B) $ \frac{1}{4\pi {\varepsilon _{0}}}\frac{2q^{2}}{l} $

C) $ \frac{1}{4\pi {\varepsilon _{0}}}\frac{3q^{2}}{l} $

D) $ \frac{1}{4\pi {\varepsilon _{0}}}\frac{4q^{2}}{l} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ U=\frac{1}{4\pi {\varepsilon _{0}}}.\frac{Q _{1}Q _{2}}{r}; $

net potential energy $ U _{net}=3\times \frac{1}{4\pi {\varepsilon _{0}}}.\frac{q^{2}}{l} $



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