Electrostatics Question 443
Question: The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2m is 2J. The potential difference between the two points will be (in volt) [RPET 1999; MP PMT 2002; AIEEE 2002]
Options:
A) 0.2
B) 8
C) 0.1
D) 0.4
Show Answer
Answer:
Correct Answer: C
Solution:
By using $ W=Q.\Delta V $
therefore $ \Delta V=\frac{2}{20}=0.1volt $
