Electrostatics Question 443

Question: The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2m is 2J. The potential difference between the two points will be (in volt) [RPET 1999; MP PMT 2002; AIEEE 2002]

Options:

A) 0.2

B) 8

C) 0.1

D) 0.4

Show Answer

Answer:

Correct Answer: C

Solution:

By using $ W=Q.\Delta V $

therefore $ \Delta V=\frac{2}{20}=0.1volt $



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