Electrostatics Question 424

Question: An electron of mass $ m $ and charge $ e $ is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be [MP PMT 2000; AMU (Engg.) 2000]

Options:

A) $ V\sqrt{e/m} $

B) $ \sqrt{eV/m} $

C) $ \sqrt{2eV/m} $

D) $ 2eV/m $

Show Answer

Answer:

Correct Answer: C

Solution:

Kinetic energy $ K=\frac{1}{2}mv^{2}=eV $

therefore $ v=\sqrt{\frac{2eV}{m}} $



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