SATHEE: Electrostatics Question 424

Electrostatics Question 424

Question: An electron of mass $m$ and charge $e$ is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be [MP PMT 2000; AMU (Engg.) 2000]

Options:

A) $V \sqrt{e / m}$

B) $\sqrt{e V / m}$

C) $\sqrt{2 e V / m}$

D) $2 e V / m$

Show Answer

Answer:

Correct Answer: C

Solution:

Kinetic energy $K = \frac{1}{2} m v^{2} = e V$

therefore $v = \sqrt{\frac{2 e V}{m}}$

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Electrostatics Question 424

Question: An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be [MP PMT 2000; AMU (Engg.) 2000]

Options:

Answer:

Solution:

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Question: An electron of mass $m$ and charge $e$ is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be [MP PMT 2000; AMU (Engg.) 2000]