Electrostatics Question 400
Question: When a proton is accelerated through 1V, then its kinetic energy will be [CBSE PMT 1999]
Options:
A) 1840 eV
B) 13.6 eV
C) 1 eV
D) 0.54 eV
Show Answer
Answer:
Correct Answer: C
Solution:
$ \Delta KE=qV=eV=e\times 1=1eV $