Electrostatics Question 400

Question: When a proton is accelerated through 1V, then its kinetic energy will be [CBSE PMT 1999]

Options:

A) 1840 eV

B) 13.6 eV

C) 1 eV

D) 0.54 eV

Show Answer

Answer:

Correct Answer: C

Solution:

$ \Delta KE=qV=eV=e\times 1=1eV $



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