Electrostatics Question 392

Question: Two point charges of $ 20\mu C $ and $ 80\mu C $ are $ 10cm $ apart. Where will the electric field strength be zero on the line joining the charges from $ 20\mu C $ charge [RPET 1997]

Options:

A) $ 0.1m $

B) $ 0.04m $

C) $ 0.033m $

D) $ 0.33m $

Show Answer

Answer:

Correct Answer: C

Solution:

Let neutral point be obtained at a distance x from 20 mC charge.

Hence at neutral point $ \frac{20}{{{(x)}^{2}}}=\frac{80}{{{(10-x)}^{2}}} $

therefore $ x=+0.033m $



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