Electrostatics Question 392
Question: Two point charges of $ 20\mu C $ and $ 80\mu C $ are $ 10cm $ apart. Where will the electric field strength be zero on the line joining the charges from $ 20\mu C $ charge [RPET 1997]
Options:
A) $ 0.1m $
B) $ 0.04m $
C) $ 0.033m $
D) $ 0.33m $
Show Answer
Answer:
Correct Answer: C
Solution:
Let neutral point be obtained at a distance x from 20 mC charge.
Hence at neutral point $ \frac{20}{{{(x)}^{2}}}=\frac{80}{{{(10-x)}^{2}}} $
therefore $ x=+0.033m $
