Electrostatics Question 373

Question: A charge of $ 5C $ experiences a force of $ 5000N $ when it is kept in a uniform electric field. What is the potential difference between two points separated by a distance of $ 1cm $ [MP PET 1997]

Options:

A) $ 10V $

B) $ 250V $

C) $ 1000V $

D) $ 2500V $

Show Answer

Answer:

Correct Answer: A

Solution:

$ F=QE=\frac{QV}{d} $

therefore $ 5000=\frac{5\times V}{{{10}^{-2}}} $

therefore $ V=10volt $



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