Electrostatics Question 373
Question: A charge of $ 5C $ experiences a force of $ 5000N $ when it is kept in a uniform electric field. What is the potential difference between two points separated by a distance of $ 1cm $ [MP PET 1997]
Options:
A) $ 10V $
B) $ 250V $
C) $ 1000V $
D) $ 2500V $
Show Answer
Answer:
Correct Answer: A
Solution:
$ F=QE=\frac{QV}{d} $
therefore $ 5000=\frac{5\times V}{{{10}^{-2}}} $
therefore $ V=10volt $
