Electrostatics Question 344

Question: If $ E $ is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to [MP PMT 2003]

Options:

A) $ E $

B) $ E^{2} $

C) $ 1/E^{2} $

D) $ E^{3} $

Show Answer

Answer:

Correct Answer: B

Solution:

Electrostatic energy density $ \frac{dU}{dV}=\frac{1}{2}K{\varepsilon _{0}}E^{2} $ $ \frac{dU}{dV}\propto E^{2} $



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