Electrostatics Question 344
Question: If $ E $ is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to [MP PMT 2003]
Options:
A) $ E $
B) $ E^{2} $
C) $ 1/E^{2} $
D) $ E^{3} $
Show Answer
Answer:
Correct Answer: B
Solution:
Electrostatic energy density $ \frac{dU}{dV}=\frac{1}{2}K{\varepsilon _{0}}E^{2} $ $ \frac{dU}{dV}\propto E^{2} $
