Electrostatics Question 336
Question: The magnitude of electric field intensity $ E $ is such that, an electron placed in it would experience an electrical force equal to its weight is given by [CPMT 1975, 80; AFMC 2001; BCECE 2003]
Options:
A) $ mge $
B) $ \frac{mg}{e} $
C) $ \frac{e}{mg} $
D) $ \frac{e^{2}}{m^{2}}g $
Show Answer
Answer:
Correct Answer: B
Solution:
According to the question, $ eE=mg $
therefore $ E=\frac{mg}{e} $
