Electrostatics Question 336

Question: The magnitude of electric field intensity $ E $ is such that, an electron placed in it would experience an electrical force equal to its weight is given by [CPMT 1975, 80; AFMC 2001; BCECE 2003]

Options:

A) $ mge $

B) $ \frac{mg}{e} $

C) $ \frac{e}{mg} $

D) $ \frac{e^{2}}{m^{2}}g $

Show Answer

Answer:

Correct Answer: B

Solution:

According to the question, $ eE=mg $

therefore $ E=\frac{mg}{e} $



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