Electrostatics Question 297

Question: Two charges+3.2×1019 and 3.2×1019C placed at 2.4AA apart form an electric dipole. It is placed in a uniform electric field of intensity 4×105volt/m . The electric dipole moment is

Options:

A) 15.36×1029 coulomb×m

B) 15.36×1019 coulomb×m

C) 7.68×1029 coulomb×m

D) 7.68×1019 coulomb×m

Show Answer

Answer:

Correct Answer: C

Solution:

Dipole moment p = q (2l) =3.2×1019×(2.4×1010)=7.68×1029C-m



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