Electrostatics Question 297
Question: Two charges$ +3.2\times {{10}^{-19}} $ and $ -3.2\times {{10}^{-19}}C $ placed at $ 2.4{AA} $ apart form an electric dipole. It is placed in a uniform electric field of intensity $ 4\times 10^{5}volt/m $ . The electric dipole moment is
Options:
A) $ 15.36\times {{10}^{-29}}\ coulomb\times m $
B) $ 15.36\times {{10}^{-19}}\ coulomb\times m $
C) $ 7.68\times {{10}^{-29}}\ coulomb\times m $
D) $ 7.68\times {{10}^{-19}}\ coulomb\times m $
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Answer:
Correct Answer: C
Solution:
Dipole moment p = q (2l) $ =3.2\times {{10}^{-19}}\times (2.4\times {{10}^{-10}})=7.68\times {{10}^{-29}}C\text{-}m $
