Electrostatics Question 293
Question: An electric dipole of moment $ \overrightarrow{p} $ is placed normal to the lines of force of electric intensity $ \overrightarrow{E} $ , then the work done in deflecting it through an angle of $ 180{}^\circ $ is [BVP 2003]
Options:
A) $ pE $
B) $ +2pE $
C) $ -2pE $
D) Zero
Show Answer
Answer:
Correct Answer: D
Solution:
Work done $ =\int _{90}^{270}{pE\sin \theta d\theta }=[-pE\cos \theta ] _{90}^{270}=0 $
