Electrostatics Question 293

Question: An electric dipole of moment $ \overrightarrow{p} $ is placed normal to the lines of force of electric intensity $ \overrightarrow{E} $ , then the work done in deflecting it through an angle of $ 180{}^\circ $ is [BVP 2003]

Options:

A) $ pE $

B) $ +2pE $

C) $ -2pE $

D) Zero

Show Answer

Answer:

Correct Answer: D

Solution:

Work done $ =\int _{90}^{270}{pE\sin \theta d\theta }=[-pE\cos \theta ] _{90}^{270}=0 $



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