Electrostatics Question 278

Question: For the circuit shown, which of the following statements is true [IIT-JEE 1999; UPSEAT 2003]

Options:

A) $ \frac{3{\varepsilon _{0}}A}{d} $

B) $ \frac{2{\varepsilon _{0}}A}{d} $

C) $ \frac{2{\varepsilon _{0}}A}{3d} $

D) $ \frac{3{\varepsilon _{0}}A}{2d} $

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Answer:

Correct Answer: D

Solution:

The given circuit can be redrawn as follows therefore $ C _{eq}=\frac{3C}{2}=\frac{3{\varepsilon _{0}}A}{2d} $



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