Electrostatics Question 278
Question: For the circuit shown, which of the following statements is true [IIT-JEE 1999; UPSEAT 2003]
Options:
A) $ \frac{3{\varepsilon _{0}}A}{d} $
B) $ \frac{2{\varepsilon _{0}}A}{d} $
C) $ \frac{2{\varepsilon _{0}}A}{3d} $
D) $ \frac{3{\varepsilon _{0}}A}{2d} $
Show Answer
Answer:
Correct Answer: D
Solution:
The given circuit can be redrawn as follows therefore $ C _{eq}=\frac{3C}{2}=\frac{3{\varepsilon _{0}}A}{2d} $
