SATHEE: Electrostatics Question 263

Electrostatics Question 263

Question: A parallel plate air capacitor has a capacitance of $100 μ μ F$ . The plates are at a distance $d$ apart. If a slab of thickness $t (t \leq d)$ and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be [MP PMT 2003]

Options:

A) $+, -, +, -, -, +$

B) $+, -, +, -, +, -$

C) $+, +, -, +, -, -$

D) $-, +, +, -, +, -$

Show Answer

Answer:

Correct Answer: D

Solution:

If the charges are arranged according to the option D, the electric fields due to P and S and due to Q and T add to zero, while due to U and R will be added up.

Electrostatics Question 263

Question: A parallel plate air capacitor has a capacitance of $100 μ μ F$ . The plates are at a distance $d$ apart. If a slab of thickness $t (t \leq d)$ and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be [MP PMT 2003]

Options:

Answer:

Solution:

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Electrostatics Question 263

Question: A parallel plate air capacitor has a capacitance of 100μμF . The plates are at a distance d apart. If a slab of thickness t(t≤d) and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be [MP PMT 2003]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A parallel plate air capacitor has a capacitance of $100 μ μ F$ . The plates are at a distance $d$ apart. If a slab of thickness $t (t \leq d)$ and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be [MP PMT 2003]