Electrostatics Question 263

Question: A parallel plate air capacitor has a capacitance of $ 100\mu \mu F $ . The plates are at a distance $ d $ apart. If a slab of thickness $ t(t\le d) $ and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be [MP PMT 2003]

Options:

A) $ +,-,+,-,-,+ $

B) $ +,-,+,-,+,- $

C) $ +,+,-,+,-,- $

D) $ -,+,+,-,+,- $

Show Answer

Answer:

Correct Answer: D

Solution:

If the charges are arranged according to the option D, the electric fields due to P and S and due to Q and T add to zero, while due to U and R will be added up.



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक