SATHEE: Electrostatics Question 243

Electrostatics Question 243

Question: In the given two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that q is so small that $\tan θ \approx \sin θ$ , then for equilibrium x is equal to [AMU 2000]

Options:

A) $2 N$

B) $6 N$

C) $8 N$

D) $20 N$

Show Answer

Answer:

Correct Answer: D

Solution:

$E_{x} = - \frac{d V}{d x} = - (6 - 8 y^{2}),$

$E_{y} = - \frac{d V}{d y} = - (- 16 x y - 8 + 6 z)$

$E_{z} = - \frac{d V}{d z} = - (6 y - 8 z)$

At origin x = y = z = 0 so, $E_{x} = - 6, E_{y} = 8$ and $E_{z} = 0$

therefore $E = \sqrt{E_{x}^{2} + E_{y}^{2}} = 10 N / C$ .

Hence force $F = Q E = 2 \times 10 = 20 N$

Electrostatics Question 243

Question: In the given two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that q is so small that $\tan θ \approx \sin θ$ , then for equilibrium x is equal to [AMU 2000]

Options:

Answer:

Solution:

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Electrostatics Question 243

Question: In the given two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that q is so small that tan⁡θ≈sin⁡θ , then for equilibrium x is equal to [AMU 2000]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: In the given two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that q is so small that $\tan θ \approx \sin θ$ , then for equilibrium x is equal to [AMU 2000]