Electrostatics Question 198
Question: Two charges each equal to $ 2\mu C $ are 0.5m apart. If both of them exist inside vacuum, then the force between them is [CPMT 2001]
Options:
A) 1.89 N
B) 2.44 N
C) 0.144 N
D) 3.144 N
Show Answer
Answer:
Correct Answer: C
Solution:
By using $ F=9\times 10^{9}.\frac{Q^{2}}{r^{2}} $
therefore $ F=9\times 10^{9}.\frac{{{(2\times {{10}^{-6}})}^{2}}}{{{(0.5)}^{2}}}=0.144N $
