Electrostatics Question 198

Question: Two charges each equal to $ 2\mu C $ are 0.5m apart. If both of them exist inside vacuum, then the force between them is [CPMT 2001]

Options:

A) 1.89 N

B) 2.44 N

C) 0.144 N

D) 3.144 N

Show Answer

Answer:

Correct Answer: C

Solution:

By using $ F=9\times 10^{9}.\frac{Q^{2}}{r^{2}} $

therefore $ F=9\times 10^{9}.\frac{{{(2\times {{10}^{-6}})}^{2}}}{{{(0.5)}^{2}}}=0.144N $



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