Electrostatics Question 188

Question: When air is replaced by a dielectric medium of constant $ k $ , the maximum force of attraction between two charges separated by a distance [CBSE PMT 1999]

Options:

A) Decreases $ k $ times

B) Remains unchanged

C) Increases $ k $ times

D) Increases $ {{k}^{-1}} $ times

Show Answer

Answer:

Correct Answer: A

Solution:

$ {F}’=\frac{1}{4\pi {\varepsilon _{0}}}\frac{q _{1}q _{2}}{r^{2}}=\frac{F}{K} $ If F is the force in air, then $ {F}’ $ is less than F since $ K>1 $ .



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