Electrostatics Question 188
Question: When air is replaced by a dielectric medium of constant $ k $ , the maximum force of attraction between two charges separated by a distance [CBSE PMT 1999]
Options:
A) Decreases $ k $ times
B) Remains unchanged
C) Increases $ k $ times
D) Increases $ {{k}^{-1}} $ times
Show Answer
Answer:
Correct Answer: A
Solution:
$ {F}’=\frac{1}{4\pi {\varepsilon _{0}}}\frac{q _{1}q _{2}}{r^{2}}=\frac{F}{K} $ If F is the force in air, then $ {F}’ $ is less than F since $ K>1 $ .
