Electro Magnetic Induction And Alternating Currents Question 96
Question: An electric lamp is connected to 220 V, 50 Hz supply. Then the peak value of voltage is [AFMC 1996]
Options:
A) 210 V
B) 211 V
C) 311 V
D) 320 V
Show Answer
Answer:
Correct Answer: C
Solution:
$ V_{0}=V_{rms}\times \sqrt{2}=220\times \sqrt{2}=310 $
