Electro Magnetic Induction And Alternating Currents Question 96

Question: An electric lamp is connected to 220 V, 50 Hz supply. Then the peak value of voltage is [AFMC 1996]

Options:

A) 210 V

B) 211 V

C) 311 V

D) 320 V

Show Answer

Answer:

Correct Answer: C

Solution:

$ V_{0}=V_{rms}\times \sqrt{2}=220\times \sqrt{2}=310 $



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