Electro Magnetic Induction And Alternating Currents Question 68
Question: A coil of 200W resistance and 1.0 H inductance is connected to an ac source of frequency $ 200/2\pi ,Hz. $ Phase angle between potential and current will be [MP PMT 2003]
Options:
A) 30o
B) 90o
C) 45o
D) 0o
Show Answer
Answer:
Correct Answer: C
Solution:
$ \tan \varphi =\frac{X_{L}}{R}=\frac{2\pi \nu L}{R}=\frac{2\pi \times \frac{200}{2\pi }\times 1}{200}=1\Rightarrow \varphi =45^{o} $
