Electro Magnetic Induction And Alternating Currents Question 68

Question: A coil of 200W resistance and 1.0 H inductance is connected to an ac source of frequency $ 200/2\pi ,Hz. $ Phase angle between potential and current will be [MP PMT 2003]

Options:

A) 30o

B) 90o

C) 45o

D) 0o

Show Answer

Answer:

Correct Answer: C

Solution:

$ \tan \varphi =\frac{X_{L}}{R}=\frac{2\pi \nu L}{R}=\frac{2\pi \times \frac{200}{2\pi }\times 1}{200}=1\Rightarrow \varphi =45^{o} $



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