Electro Magnetic Induction And Alternating Currents Question 593

Question: When the current change from + 2A to ? 2A in 0.05 second, an e.m.f. of 8 V is induced in a coil. The coefficient of self-induction of the coil is [AIEEE 2003]

Options:

A) 0.1 H

B) 0.2 H

C) 0.4 H

D) 0.8 H

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Answer:

Correct Answer: A

Solution:

$ e=L\frac{di}{dt}\Rightarrow 8=L\times \frac{( 2-( -2 ) )}{0.05}\Rightarrow L=0.1H $



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