Electro Magnetic Induction And Alternating Currents Question 593
Question: When the current change from + 2A to ? 2A in 0.05 second, an e.m.f. of 8 V is induced in a coil. The coefficient of self-induction of the coil is [AIEEE 2003]
Options:
A) 0.1 H
B) 0.2 H
C) 0.4 H
D) 0.8 H
Show Answer
Answer:
Correct Answer: A
Solution:
$ e=L\frac{di}{dt}\Rightarrow 8=L\times \frac{( 2-( -2 ) )}{0.05}\Rightarrow L=0.1H $
