Electro Magnetic Induction And Alternating Currents Question 589
Question: The self-induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 ampere/second is [DPMT 2002]
Options:
A) $ 8\times {{10}^{-4}},V $
B) $ 8\times {{10}^{-5}},V $
C) $ 20,V $
D) $ 125,V $
Show Answer
Answer:
Correct Answer: C
Solution:
$ e=L\frac{di}{dt}\Rightarrow e=0.1\times 200=20V $
