Electro Magnetic Induction And Alternating Currents Question 589

Question: The self-induced e.m.f. in a 0.1 H coil when the current in it is changing at the rate of 200 ampere/second is [DPMT 2002]

Options:

A) $ 8\times {{10}^{-4}},V $

B) $ 8\times {{10}^{-5}},V $

C) $ 20,V $

D) $ 125,V $

Show Answer

Answer:

Correct Answer: C

Solution:

$ e=L\frac{di}{dt}\Rightarrow e=0.1\times 200=20V $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक